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Java Program to find Smallest element in the array

Get array size n and n elements of array, then find the smallest element among those elements.

Sample Input 1:

5 5 7 9 3 1

Sample Output 1:

1

Try your Solution

Strongly recommended to Solve it on your own, Don't directly go to the solution given below.

public class Hello { public static void main(String args[]) { //Write your code here } }

Program or Solution

				
			
					
import java.util.*;
class SmaArr
{
  public static void main(String args[])
  {
     int size,i,num;
     Scanner sc=new Scanner(System.in);
     System.out.println("Enter Size Of Array:");
     size=sc.nextInt();
     int a[]=new int[100];
     System.out.println("Enter The Array Elements:\n");
     for(i=0;i<size;i++)
        {
            a[i]=sc.nextInt();

	}
     int min=a[0];
     for(i=0;i<size;i++)
        {
            if(a[i]<min)
              {
                min=a[i];
              }

       }
       System.out.println("The Smallest Element In The Array Is:"+min);
  }
}

Program Explanation

Array is a Collection of data with same type.

1. Get the size of the Array

2. Create a array with the given size (Array has 0 to size-1 index to access every location)









        0                        1                        2                         3              ......             size-2                  size-1


3. Get Inputs for Array (See Previous Problems for detail)

4. Initially assume a[0] is the largest number

     max = a[0]


In the second For Loop,

i starts at 0, and incremented by 1 after every iteration. iteration stops when i is equal to size.

in every iteration the  if(a[i]<min) checks the located element in current index is less than min

if the element located in any position is less than min, then assign the element as min by using min= a[i]

finally min holds the minimum value in the array after all the iterations.

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