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C Program to find Smallest element in the array using pointers

Get array size n and n elements of array, then find the smallest element among those elements.

Sample Input 1:

5 5 7 9 3 1

sample Output 1:

1

Try your Solution

Strongly recommended to Solve it on your own, Don't directly go to the solution given below.

#include<stdio.h> int main() { //write your code here }

Program or Solution

				
			
					
#include<stdio.h>
#include<stdlib.h>
int main()
{
	int *a,n,i,min;
	printf("Enter size of array:");
	scanf("%d",&n);

	a=calloc(sizeof(int),n);
	printf("Enter %d Elements:",n);
	for(i=0;i<n;i++)
	{
		scanf("%d",a+i);
	}
	
	min=*a;
	
	for(i=1;i<n;i++)
	{
		if(*(a+i)<min)
		{
			min=*(a+i);
		}
		
	}

	printf("%d",min);
	return 0;		
}

Program Explanation

calloc() is predefined function allocates memory of specified bytes.

Number of bytes is specified as (4,n), it means n 4 bytes.

Since we are using integers, specified as 4 bytes.

*a denotes first four bytes, *(a+1) denotes second four bytes, *(a+2) denotes third four bytes and so on., i is initialized to 0 and incremented by 1 at each iteration of both the for loops.

First for loop reads n input numbers from user and stores them in array a[] from location 0 to n-1 Initially assign the element located at 0 to max using min =*a.

using second for loop visit each location serially from 1 to n-1.

if the element located in any position is lesser than min, then assign the element as max by using min = *(a+i) finally min holds the minimum value in the list.

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