Covert Lowercase characters to Uppercase Characters using Pointers
Get a String and convert the upper case characters to lower case Characters
Sample Input 1:
Hello
Sample Output 1:
hello
Try your Solution
Strongly recommended to Solve it on your own, Don't directly go to the solution given below.
#include<stdio.h>
int main()
{
//write your code here
}
Program or Solution
#include<stdio.h>
#include<stdlib.h>
int main()
{
char *str;
int i = 0;
str=calloc(sizeof(char),50);
fgets(str,50,stdin);
while(*(str+i)!='\0')
{
if(*(str+i)>=97 && *(str+i)<=122)
{
*(str+i)=*(str+i)-32;
}
i++;
}
printf("%s",str);
return 0;
}
Program Explanation
Get a String using fgets() function.
Str -> reads the string and stores it in str.
50 -> reads maximum of 50 characters stdin-> reads character from keyboard ASCII value of A to Z is 65 - 90 and a to z is 97 to 122.
for loop iterates and check each character whether it is s A to Z, if it is in A to Z then increment it with 32 to get Lower Case.
Comments
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