# C Program to Arithmetic Calculator using switch case Statements

Get a binary arithmetic expression and solve the expression.

Sample Input 1:

12+9

Sample Output 1:

21

Sample Input 2:

4*5

Sample Output 2:

20

#### Try your Solution

Strongly recommended to Solve it on your own, Don't directly go to the solution given below.

#include<stdio.h>
int main()
{
//write your code here
}

#### Program or Solution

```
```
#include<stdio.h>
int main()
{
int num1,num2,output;
char operator;
printf("Enter a binary expression:");
scanf("%d %c %d",&num1,&operator,&num2);
switch(operator)
{
case '+':
output=num1+num2;
break;
case '-':
output=num1-num2;
break;
case '*':
output=num1*num2;
break;
case '/':
output=num1/num2;
break;
case '%':
output=num1%num2;
break;
default :
printf("invalid operation");
break;
}
printf("%d",output);
return 0;
}

#### Program Explanation

Based on the second character operator, instructions in any one of the case will be executed.#### Comments

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